[Javalist] resteasy

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Csak hogy meglegyen egy resteasy-s megoldas is:
web.xml
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee  
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
	<servlet>
		<servlet-name>Resteasy</servlet-name>
		<servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
	</servlet>

	<context-param>
		<param-name>resteasy.scan</param-name>
		<param-value>true</param-value>
	</context-param>

   <servlet-mapping>
                 <servlet-name>Resteasy</servlet-name>
                 <url-pattern>/*</url-pattern>
         </servlet-mapping>

</web-app>

java kod:
package test;

import javax.ws.rs.GET;
import javax.ws.rs.Path;


@Path("resource")
public class TestResource {

	@GET
	public String foo() {
		return "E!";
	}
}

Ez nekem stock jboss 6.1-al mukodik.


On Fri, 23 Dec 2011 14:40:30 +0100, András Csányi <sayusi.ando at gmail.com>  
wrote:

> 2011/12/23 Avramucz István <avramucz at gmail.com>:
>> A Jersey gyakorlatilag csak ennyit igényel a web.xml-ben:
>>
>> <servlet>
>> <servlet-name>ServletAdaptor</servlet-name>
>> <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
>> <load-on-startup>1</load-on-startup>
>> </servlet>
>> <servlet-mapping>
>> <servlet-name>ServletAdaptor</servlet-name>
>> <url-pattern>/rest/*</url-pattern>
>> </servlet-mapping>
>
> Köszi ezt is és ez eddigieket is! :)
>


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